Algebra Question!

[Intelligent]

This is a grade 7-8 algebra question! How many of you can solve it?

(B-30)÷4=2x(9+A)x2+(Ax4+2)=20

Please enter your answers and show your work below.

 

[MultiGod]

What is your question, really. Is it to search for B, or A? or both?

1st,
20=(b-30)/4
80=b-30
110=b

2nd,
20=2(9+a)*2+(a*4+2)
20=18+2a*2+(4a+2)
Whereas
20=18+4a+4a+2
20=20+8a
so,
a=0

Then,
b=110, and
a=0

for me it's pretty easy.

 

[Syth]

Yea, I had no idea.

How am I going to pass my maths exam in two weeks.

 

[MultiGod]

It's actually easy, 1st you take the first equation and compare it to 20. That way you will get B. Then take the second equation and compare it with 20. Then you'll obtain A.

 

[En_Fuego]

(B-30)÷4=20
B-30 = 80
B = 110

2x(9+A)x2+(Ax4+2)=20
4x(9+A)+(Ax4+2) = 20
(36x+4xA)+(Ax4+2) = 20
36x+8xA+2 = 20
(36x+8x+2)/A = 20 (Not sure if from here on this is right. Been a while since I did alg)
(44x+2)/A = 20
44x/A = 18
44x = 18A
uhhhhhhhhhhhhhhhhhhhhhhhhhhhh what'd I do wrong here? I find it hard to believe that I passed my 6th grade Algebra class with top marks...

edit: nvm I tried using polynomial method I think. Kill me x[

 

[HINDYhat]

En_Fuego, the 'x's aren't variables. They're multiplication operators. Also, you got it all wrong anyway.

 

[En_Fuego]

Yeah, that's why I said I totally ruined it lol.

This is why we should use *...

or you could just use coefficients like a normal person I suppose...

on a related note: did you get this problem out of a textbook?

 

[HINDYhat]

Nobody even got it right. Jeez, this is ridiculously simple too.

20 = 2*(A + 9)*2 + (4A + 2)
20 = 4(A + 9) + (4A + 2)
20 = 4A + 36 + 4A + 2
20 = 8A + 38
-18 = 8A
A = -9/4

moar multivariate calculus plx

 

[D a w n]

(B-30)÷4=20
=B-30=80
=B=110
and:

2x(9+A)x2+4A+2=20
= 38+8A=20
=8A=-18
=A= -2,25

 

[En_Fuego]

(B-30)÷4=20
2x(9+A)x2+4A+2=20
= 38+8A=20
=8A=-18
=A= -2,25

How'd you go from 4(9+A) to 38+8A?

 

[busterkomo]

2x(9+A)x2+4A+2=20

 

[Destroyer25]

Cant you only have 1 = sign per equation lol?

 

[HINDYhat]

2 = 2 = 2

I just blew your mind.

 

[Diehard@Azeroth]

im pretty sure subsititon would work for this, the two equations = 20 sign would work too tho >_>

 

[PurplePoot]

I match your grade 8 algebra question and raise you a first year university math major algebra question.

Evaluate the sum

for all n≥0 and prove that your answer is correct.

 

[WILL THE ALMIGHTY]

Nobody even got it right. Jeez, this is ridiculously simple too.

20 = 2*(A + 9)*2 + (4A + 2)
20 = 4(A + 9) + (4A + 2)
20 = 4A + 36 + 4A + 2
20 = 8A + 38
-18 = 8A
A = -9/4

moar multivariate calculus plx

No one here is old or smart enough to know Calculus, Hindy.

 

[trolman]

Lol math sucks

 

[WILL THE ALMIGHTY]

See what I mean?

 

[HINDYhat]

I counter your algebra question with an impossible indefinite integral!

 

[PurplePoot]

I match your impossible indefinite integral with wolfram|alpha!

integral sqrt(1+x^3) dx = (2 (x^4+(-1)^(1/6) 3^(3/4) sqrt(-(-1)^(1/6) (x+(-1)^(2/3))) sqrt((-1)^(2/3) x^2+(-1)^(1/3) x+1) F(sin^(-1)(sqrt(-(-1)^(5/6) (x+1))/3^(1/4))|(-1)^(1/3))+x))/(5 sqrt(x^3+1))+constant

 

[TheBlooddancer]

And i beat you all, giving you the the question 'What is the last digit of pi'.

 

[En_Fuego]

And i beat you all, giving you the the question 'What is the last digit of pi'.

4

I rounded.

 

[MultiGod]

Nope, the last digit of pi is: 7. Because the exact(not really exact) value of pi is 22/7=3.142857. Yeah, but 3.14 is commonly used. So I guess 4 is the answer.

 

[HINDYhat]

Great. 22/7 gives me the first 3 digits of pi.

What the fuck? Why does anyone actually remember that? Why not just memorize the first three digits of pi instead of memorizing the digits 2, 2 and 7?

Also, ned moar math community plx.

 

[MultiGod]

try calculating the size of a circle with radius 14 using pi=3.14 and pi=22/7. Is it the same?

 

[HINDYhat]

How about just use a calculator or keep exact values...

 

[PurplePoot]

try calculating the size of a circle with radius 14 using pi=3.14 and pi=22/7. Is it the same?

Try calculating it with the real value of pi compared to 22/7?

 

[WILL THE ALMIGHTY]

Since when does pi = 22/7? What the hell do they teach you at your school?

integral sqrt(1+x^3) dx = (2 (x^4+(-1)^(1/6) 3^(3/4) sqrt(-(-1)^(1/6) (x+(-1)^(2/3))) sqrt((-1)^(2/3) x^2+(-1)^(1/3) x+1) F(sin^(-1)(sqrt(-(-1)^(5/6) (x+1))/3^(1/4))|(-1)^(1/3))+x))/(5 sqrt(x^3+1))+constant

42.

 

[HINDYhat]

That answer is a lie by the way.

 

[Destroyer25]

I match your impossible indefinite integral with wolfram|alpha!

integral sqrt(1+x^3) dx = (2 (x^4+(-1)^(1/6) 3^(3/4) sqrt(-(-1)^(1/6) (x+(-1)^(2/3))) sqrt((-1)^(2/3) x^2+(-1)^(1/3) x+1) F(sin^(-1)(sqrt(-(-1)^(5/6) (x+1))/3^(1/4))|(-1)^(1/3))+x))/(5 sqrt(x^3+1))+constant

Is this what you do for fun.....?

 

[PurplePoot]

Is this what you do for fun.....?

Something tells me you didn't read the first line.

http://www.wolframalpha.com/

Also, the answer is a lie as HINDY said.

 

[TheBlooddancer]

Nope, the last digit of pi is: 7. Because the exact(not really exact) value of pi is 22/7=3.142857. Yeah, but 3.14 is commonly used. So I guess 4 is the answer.

No.

3.1415926535897932 is what i've memorized, but as you keep adding digits, they become less and less note-worthy.

 

[Intelligent]

I made this algebra question.

 

[Aesthetics]

I looked at the poll's results, and saw that "boring" had the most votes.

So I thought: What a load of crap.

 

[Vampiro320]

I allways feel really dumb, but reading what you guys said about this one...lowers my self esteem just a little.