Safe way to get the middle of 2 angles value?

[Ofel]

If:
angle1 = 90
angle2 = 180
midAngle = 135 <-- Okay, no problem.

If:
angle1 = 360
angle2 = 90
midAngle = 225 (wrong: not a middle between 360 and 90, toward south) <-- Which must supposedly be 45 (toward north)

Formula used:
midAngle = angle1 + ( (angle2 - angle1) / 2 )

Any suggestion?

 

[Chaosy]

(angle1 + angle2) / 2 ?

 

[Ofel]

(angle1 + angle2) / 2 ?

It still doesn't give the proper middle angle between those two.
225 is not the middle of 90 and 360/zero, 495 isn't either.

 

[Wareditor]

Use a modulo 360 on angle 1 or use a module 180 on the end result.
I would advise using radians and using a modulo 2Pi on angle 1 or modulo Pi on the end result.

 

[Ofel]

Use a modulo 360 on angle 1 or use a module 180 on the end result.
I would advise using radians and using a modulo 2Pi on angle 1 or modulo Pi on the end result.

I kinda know what is it and how but, I might just need quick example. *_*
I'll be back tomorrow, it's late night here.

 

[Chaosy]

Err, what?

It gives the middle angle, just not the one you might expect.

There are two answers, in this image 45 is the closest middle, but the one at the opposite end is also equally in the middle.

Either that or I am retarded.

 

[Jampion]

Assuming that both angle1 and angle2 are >= 0 and < 360:
midAngle = (angle1 + angle2) /2

if abs(angle1-angle2) > 180
midAngle = midAngle - 180

If you add this condition after that, you should get the angle you want.

 

[Dr Super Good]

As pointed out above...

There are technically 2 middle angles due to the circular nature of angles. Unless the 2 angles are exactly 180 degrees apart then one of the middle angles will be closer to the angles than the other middle angle.

A stupid way of finding the angle...
midAngle1 = (angle1 + angle2) /2
midAngle2 = midAngle1 + 180 degrees

One can use modulus to restrict the range to between 0 and 360 degrees if one wants.

To find which mid angle is the closest to the original angles...

Cosine(midAngle1 - angle1) > Cosine(midAngle2 - angle1)
If true then midAngle1 is closer, otherwise midAngle2 is closer. Note that there will be a bias towards midAngle1 in the case that angle1 and angle2 are exactly 180 degrees apart, however this is needed to solve the problem of both mid angles being exactly 90 degrees from both angle1 and angle2.