This is confusing...
In the above experiment, 50.0cm(cubic volume) of HCl acid of concentration 2.0mol/dm(cubic) was used. 6.4g of SrCl2.6H20 was made.
Calculate the percentage yield.
Number of moles of HCl used = 0.1mol (Correct)
Number of moles of SrCl2.6H20 which could be formed = I thought it is 0.1 mol. but its wrong...Why?
Mass of one mole of SrCl2.6H20 is 267g.
Theoretical yield of SrCl2.6H20= .........
Percentage yield= ..........
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I am stuck at the part of getting the mole of SrCl2.6H20. The correct answer is 0.05 mole but I got 0.1 mole. Any solutions?