Parabola ... sort of?

[baassee]

hey

just anyone that got any idea how to calculate a good parabola function and not the usual one, with that I mean not a raise and reach half it goes down.

If anyone is good at math lawl (only going for the first course of 5 in math atm so not so good yet )

to make a parabola that goes like this



straight falling down like rain of chaos basiclly, would be appriciated if someone could come up with this, going to use it for a spell function and ofc I can make it otherwise with dummy spells and such but thought this would be ehum ... better?

 

[Maker]

So you have the offset (x) and height (y). Z is sqrt(x² + y²). You can change the angle by altering the ratio between x and y.

 

[baassee]

thank you very much, will test this out later today + rep

 

[meOme]

That's not a parabola, that's a straight line. oÔ

 

[wolfman]

You could also do it by using whatever angle you want. Say you want it to come down at a 45° angle. then you can do tan45 = y/x using makers little diagram. So you could change the equation to set the height y = tan45 * x. You can make it move forward 5 and it will move down to the appropriate height to get a 45° angle to the ground.

Every .02 seconds
Set HeightOffset = tan45 * 5
set height = current height of unit - HeightOffset
Set flying height of picked unit to height at 0 // setting units flying height to a rate of 0 sets its height instantly
move unit to position of picked unit offset by 5 towards facing of picked unit

I think something like that would work.
And btw i dont think getting the distance of z will help at all :/

An easier yet less accurate way to do this could be to simply move the unit forward and do Set units flying height to 0 at 50

 

[Shdow89]

Shadow1500 Jump Parabola

function JumpParabola takes real dist, real maxdist,real maxheight returns real
    local real t = (dist*2)/maxdist-1
    return (-t*t+1)*maxheight
endfunction

Here's a JASS jump parabola made by Shadow1500. In GUI it would look like:

GUI Version

• Jump Parabola GUI
  • Events
  • Conditions
  • Actions
    • Set dist = (Distance between (Position of (Triggering unit)) and (Position of (Triggering unit)))
    • Set maxDist = 650.00
    • Set maxHeight = 500.00
    • Set t = ((dist x 2.00) / (maxDist - 1.00))
    • Custom script: set udg_final = ( - udg_t * udg_t + 1 ) * udg_maxHeight
    • Animation - Change (Triggering unit) flying height to final at 0.00

You can set here maxDist - Distance Achived, dist - moving dist, maxHeight - maximum height that unit achieves. I'm not really sure how good is this parabola, but I used it in my spell, and it worked fine. Hope this helps.

THIS IS NOT MADE BY ME. If you use give credit to Shadow1500.

 

[xD.Schurke]

the formula is sqrt(delta(x)²+delta(y)²)
so in other words sqrt((x₂-x₁)²+(y₂-y₁)²)

 

[HINDYhat]

[...]
to make a parabola that goes like this

straight falling down [...]

Yeaaaah... that's not a parabola. Rather, that's a straight line. This is a parabola

You can't just go and call every graph and line you see a parabola now. Git'yer terminology right!

 

[baassee]

I said sort of parabola

I will try to test it all, see which will perform the best, thank you all

 

[GhostWolf]

y(x) = mx + a

 

[wolfman]

y(x) = mx + a This might be the easiest way to do it. y = mx + b is more common than what u said i think but its rly the same thing :/
y = the height offset
x = the distance moved forward
m = the slope (rise over run) so -3/4 slope would make it go down 3 and over 4
b = the starting height

 

[Rmx]

There is also another one.

You have -

Height = 300
Distance = 1000
Speed = 10

The formula when you reach distance 500 is ..

Set Height = Height - X.

X = ( ( Speed / Distance ) x Height )

Best and most lovely

Remember when the hero reaches half distance

 

[Mooglefrooglian]

This isn't a sort of parabola at all, it's a linear function. >.>

A parabola has curve, that being it's most basic definition. It is in the form Ax^2 + bx + c.

 

[YourNameHere]

This isn't a sort of parabola at all, it's a linear function. >.>

A parabola has curve, that being it's most basic definition. It is in the form Ax^2 + bx + c.

YES WE ALL GOT IT KNOW

goddamnit.

 

[Rmx]

Check my upper post baassee for the ultimate solution

 

[baassee]

that's why I mentioned the thing about "sort of" ^^

thank you remix, will check it out to but found out that a few of those above work really well too