Hey guys!

[Teh_Ephy]

a = b
ab = b²
...
a² - b² = a(a - b)
(a + b)(a - b) = a(a - b)
(a + b) = a
2a = a
2 = 1

 

[wereguy2]

/me cries

 

[reza sword2]

a = b
ab = b²
...
a² - b² = a(a - b)
(a + b)(a - b) = a(a - b)
(a + b) = a
2a = a
2 = 1

What kind of evil is that?

a = 1
b = 1

I suppose...

 

[Mechanical Man]

Error: divide by zero

 

[Joe-black-5]

1=1
1x1=1
...
1-1=1(1-1)
(1+1)(1-1)=1(1-1)

(1+1)/(1-1)=1/(1-1) ??

 

[bounty hunter2]

sin(a)+sin(y) = [2sin(a+y)/2] * [cos(x-y)/2]

-1 =< a,y =<1

a,y e Z

 

[The_wand_mirror]

I had a 1,8/10 for a test today which included this kind of crap.

 

[Need_O2]

I know those
x=1
x²= x
x²-1 = x-1
(x-1)(x+1) = x-1
x+1 = 1
x=0
1=0

The main reason of the bugs is "if you simplyfy 2 statements those are equal to 0 you ruin the calculation"
Which is main reason of why "Limit" problems in mathematic can be difficult

You know
xy = ay => x=a
but if y is 0 its not so you cant simplyfy the 0s

if you do it all calculations are wrong
0*100000000 = 0*500
100000000=500

 

[Anachron]

Never devine through 0.

 

[HailFireer]

I dont get it. Eqvasion is corect..
I had 25 points out of 80 on a test... Its an F. Aldo mostly cuz of stupid mistakes. Wer having a redo luckaly.

 

[Aeroblyctos]

x = y.

 

[Anachron]

a = b ( 1 == 1 )
ab = b2 ( (1 == 1 ) = true)
...
a2 - b2 = a(a - b) ( 1 - 1 == 1 * ( 1 - 1 ) / 1 * 0 = false )
(a + b)(a - b) = a(a - b) ( a2 - ab + ab - b2 == 2 * ( a - b )

= 0 == 0 = true
​

 

[Need_O2]

does anyone hear me ???
you cant simplfy 2 statements those equal to 0
math doesnt allow this

so your calculation is not correct

 

[Anachron]

That is what I am writing the whole time.

 

[-Berz-]

It can be any number actually since a = b, it can be 2 = 2, 666 = 666, 1337 = 1337

2x2 = 2^2, 3x3 = 3^2

Dunno those goes for the first...

But i guess its 1337 ^^

 

[Palaslayer]

it is not possible because one statement says that a = b
but a has to be null or

2a = a is false....

 

[TheBlooddancer]

2 = 1

Just divide by zero, and everything will be fine.

 

[Palaslayer]

roflmaolol

y, that should be it ^^

 

[Dark Master]

I Think about 0......

 

[Teh_Ephy]

Mechanical Man had it right in the third reply, the jackass. Joe-black-5 and Anachron also had it right. Dividing by (a - b) is dividing by (a - a) is dividing by zero. Whatever the hell else the rest of you are talking about is weird as fuck.

 

[Elenai]

I hate math...

 

[bounty hunter2]

I hate math...

I love math

 

[Shados]

0^n = 0
n^0 = 1
0^0 = The fuck?

 

[wereguy2]

/me cries again and agrees with Elenai D:

 

[Captain Griffen]

Maths is logically valid. It can be proved so. But you have to remember not to use operators on things outside of their domain. The ordered pair taken by the operator "divide by" has its domain for the second member as all non-zero numbers.

 

[TheDivineBoss]

a = b
ab = b²
...
a² - b² = a(a - b)
(a + b)(a - b) = a(a - b)
(a + b) = a
2a = a
2 = 1

If we take:
a = 2
b = 2

You get:

2 = 2
2x2 = 2²
...
2² - 2² = 2(2 - 2)
(2 + 2)(2 - 2) = 2(2 - 2)
(2 + 2) = 2
2x2 = 2
something = something

I dunno.

 

[Palaslayer]

I love math

i can't say no more thing ^^

math!

 

[Joe-black-5]

Math > all

 

[Palaslayer]

correct

 

[Dark Master]

2x2=2

What is this?! 2x2=4....

Anything to say?

 

[Anachron]

(2 + 2)(2 - 2) = 2(2 - 2)

2 * 0 = Fail, you devide with 0.

 

[Palaslayer]

thats 4*0 = 2*0

which would be correct because it is 0=0

where is there a / ????

 

[Dark Master]

Yes, but 2a=a wouldn`t be right 2x2=4 not 2

 

[Palaslayer]

i know that and i told that before....

 

[Dark Master]

Sorry then.

 

[Palaslayer]

np for me, how did you get neg rep?

 

[Dark Master]

Bah, I said I don`t believe in God.

 

[Anachron]

thats 4*0 = 2*0

which would be correct because it is 0=0

where is there a / ????

Fail? Double * 0 is double Fail. You are not allowed to do it once, also you are not allowed to do it twice. Don't you understand?

 

[Palaslayer]

sure i can do 1*0 = 0

i cannot do 1/0 thats true

Bah, I said I don`t believe in God.

hehe, it is freedom of opinion oO

why the hag...

 

[Dark Master]

Yes, but...

 

[Anachron]

sure i can do 1*0 = 0

i cannot do 1/0 thats true

Ye but 1 * 0 = 0 and 2 * 0 = 0 so its not 2=1 but 0 = 0

 

[Dark Master]

Yes, but 2=1 can`t be...

 

[Captain Griffen]

2 != 1 does not preclude 0 == 0 or 0*2 == 0*1...

 

[Teh_Ephy]

[highlight]Jesus Christ people, Mechanical Man said four posts into the thread that I divided by zero to do that. Learn to read before you post, the current problem we are working on is:

n⁰ = 1
0ⁿ = 0
0⁰ = ?[/code]

What is this?! 2x2=4....

[highlight]Anything to say?[/code]

Learn to read. Like, at least the first post in the thread. God damn.

Bah, I said I don`t believe in God.

No, you got -rep for telling people that they shouldn't believe in God either, in a hugely annoying way to boot.

 

[Pyritie]

Some math professors say it's = 1, most say it's undefined. There isn't any real proof for either one at the moment, at least not that I know of.

 

[Captain Griffen]

All maths is actually derived inductively pretty much.

Here is the correct starting position:

n^1 = n
n^(m+1) = n*n^m

Hence, 0^0 is undefined.

 

[bounty hunter2]

n^0=1

n=!0?

or if n == 0 can be true

then 0^0=1

 

[Captain Griffen]

n^0=1

n=!0?

or if n == 0 can be true

then 0^0=1

No where in the fundamentals of maths does it say n^0 == 1. It is derived, and the derivation is conditional upon n != 0.

 

[bounty hunter2]

Then indeed it can't be 1. If the derivation conditional states n != 0.

 

[Samuraid]

Deja vu? http://www.hiveworkshop.com/forums/f478/more-math-stuff-44302/