[MATH] Strong at Night, Weak During Day spell

[Titanhex]

So I want to create a spell that is stronger towards midnight (0.00) and weaker towards day. (12.00)

The problem is, the second before midnight is 23.99, so the GetFloatGameState command in JASS has to be converted into an algorithm that properly creates a zenith at midnight and a nadir at noon.

Does anyone know how to convert these numbers to do this?

 

[RobertMKD]

When the daytime becomes 00:00> and <12:00 then set a boolean Night to true, when it becomes 12:00> and <23:59 set Night to false.

 

[Garfield1337]

Would a function like this fit your needs?

graph

The formula is ((cos(time * pi / 12) + 1) / 2) * (max - min) + min
Where
"time" is daytime between 0 and 24.
"min" and "max" are minimum and maximum values the function can yield.

 

[RobertMKD]

Ah now I get what you want, but I'm not using JASS so I know how to do it in GUI only. Garfield's reply should solve your problem.

 

[Nichilus]

Just a note here:

When the daytime becomes 00:00> and <12:00 then set a boolean Night to true, when it becomes 12:00> and <23:59 set Night to false.

Your logic here is wrong.
For example 11:00 AM is not exactly night. If anything, he would need to set 6 AM as start of day and 6 PM as start of night (this is the default day/night time in wc3).

 

[RobertMKD]

Just a note here:

Your logic here is wrong.
For example 11:00 AM is not exactly night. If anything, he would need to set 6 AM as start of day and 6 PM as start of night (this is the default day/night time in wc3).

Yes I know, but that can be changed, so when he said he wants the unit get stronger towards 00:00 and weaker towards 12:00, I thought his night begins at 00:00 and day at 12:00 and he wants the unit to become stronger when night begins, but I got what he was sayin' later.

 

[Dr Super Good]

As Garfield1337 said, use the sine/cosine functions by converting the time into an angle. Due to the circular nature of angles it can be used to mask the discontinuity with time. You just need to make sure that the full day fits exactly into an integer multiple of a circle (360 degrees or 2pi is a full circle).

 

[Titanhex]

Thanks! That's definitely the algorithm I was looking for.

It works for boosting skills during the day, but I'm not sure how to inverse the algorithm for night. Would I use sin instead of cos?

 

[Flux]

It works for boosting skills during the day, but I'm not sure how to inverse the algorithm for night. Would I use sin instead of cos?

That equation already represents for both day and night. You will only use a single equation mentioned by Garfield1337 which is a cosine. Using sine will shift the phase by 90 degrees and will not invert. Adding a pi phase offset on the cosine will invert it making the max at 12 and min at 0.

 

[Garfield1337]

Thanks! That's definitely the algorithm I was looking for.

It works for boosting skills during the day, but I'm not sure how to inverse the algorithm for night. Would I use sin instead of cos?

The value will tend towards minimum during night, so there's no need to invert anything.

EDIT: towards maximum*

 

[Flux]

The value will tend towards minimum during night, so there's no need to invert anything.

Wait, isn't night time happens at 18 not 12.
Anyway, just a quick change at the min max values and its good to go.

 

[RobertMKD]

Wait, isn't night time happens at 18 not 12.
Anyway, just a quick change at the min max values and its good to go.

0 is the middle of the night, he want's his unit to be the strongest at midnight and the weakest at noon - 12.

 

[Nichilus]

That doesn't make any sense.

 

[SAUS]

For inverting it, you could also calculate the value and then just do (max - value).