[Solved] Syntax Error, Unexpected:

[TheAncient]

I am not dumb. I know coding. But this is driving me up the wall. It has to be something stupidly simple. But after staring at it for an hour and going over it character by character, I feel my eyes are twisting.

https://1drv.ms/i/s!ArS8h72gEKYqkGp_5J4gCwaeQSDU

https://1drv.ms/i/s!ArS8h72gEKYqkGtqH4ZDZ9Nbyibu

 

[TriggerHappy]

Post the code in [code=jass][/code] tags

 

[IcemanBo]

Only at declaration the variable type is needed.

local unit u
set unit u = ...

-->

local unit u
set u = ...

 

[LeP]

I think i have seen this error before from beginners. If you give me a good error message i can special-case this in pjass.
This is what i currently have:

$ cat test.j
type unit extends handle

function foo takes nothing returns nothing
    local unit u
    local unit v
    set unit u = null
    set u unit = null
    set v u = null
endfunction

$ ./pjass test.j
test.j:6: >unit< u is an error here. The type only needs to be stated at declartion time
test.j:7: u >unit< is an error here. The type only needs to be stated at declartion time
test.j:8: Unexpected 'u'
test.j failed with 3 errors
Parse failed: 3 errors total

 

[TheAncient]

Only at declaration the variable type is needed.

local unit u
set unit u = ...

-->

local unit u
set u = ...

OH MY FREAKING DERP!
I feel like an idiot now...

Thank you. I fixed it.

 

[Pyrogasm]

I think i have seen this error before from beginners. If you give me a good error message i can special-case this in pjass.

"variable u type respecified/restated"? It's not redeclared but there has to be a good word for it.

 

[Dr Super Good]

"variable u type respecified/restated"? It's not redeclared but there has to be a good word for it.

The assignment statement is not valid. Nowhere in an assignement statement is a type expected or even allowed.

// local declaration with optional definition
local {type} *varname* (= [expression of {type}])

// local assignment
set *varname* = [expression of {type}]

where...

• {} represent a previously declared type name
• ## represent a declared variable name that is not a key word or a type name.
• () represent the enclosed is optional
• [] represent an expression governed by other syntax rules not covered here

I am sure there is a better and more clear way to describe the syntax. Just I am not experienced with such.