Physics Angular velocity

[Manoo]

Hey, I have one question is there somekind of formula for air resistance in angular velocity. I can't find it anywhere. I only found drag force that looks like:

F = 0.5 c * ρ * A * v^2

F - is the drag force,
ρ - is the density of the fluid,
v - is the speed of the object relative to the fluid,
A - is the cross-sectional area, and
c - is the drag coefficient – a dimensionless number.

But I'm sure this formula doesn't fit with angular velocity only with linear velocity.

 

[deathismyfriend]

I think you need this formula since the one you are using deals with fluid based drag.

Fw = Cd * d * A * v^2 / 2

where
Cd = Drag Coefficient of sphere // You should assume this is a constant for your wind speeds
d=air density
A= Area of influence
v=Velocity of wind

 

[Adiktuz]

Take a look here, it seems to discuss Drag Torque http://physics.stackexchange.com/questions/56796/drag-on-a-spinning-ball-in-fluid

 

[Manoo]

Adiktuz, Yea I saw this link, but as I suspect this formula only fits for spheres, but I need formula for other geometry forms like box, cylindre.

 

[Adiktuz]

I see... you can probably try to use it still, at least to approximate values...

 

[Manoo]

Adiktuz, I'm making directx engine for game, so atleast I want to make physics as realistic as possible. Of course I think I'm not going to make all possibly aspects of physics, because game resources are limited .

 

[Adiktuz]

I guess approximates will work for the drag, unless the values are too far

or maybe try if you can use existing ones like Havok?

 

[Dr Super Good]

I'm making directx engine for game, so atleast I want to make physics as realistic as possible. Of course I think I'm not going to make all possibly aspects of physics, because game resources are limited .

What does using the DirectX API have to do with physics? Are you trying to tell us that you will use Direct Compute to hardware accelerate physics in your game?

 

[Manoo]

Ah nevemind I think i'm going to stick with Bullet Physics . Ty for your help.