Is there a way to simplify my calculation?

[Deleted member 219079]

How could I simplify this calculation?

 

[PurgeandFire]

There isn't an inherent way to simplify that. What is the context of that formula? What are you using it for?

 

[Deleted member 219079]

Having pythagors on 3 numbers instead of 2, normally it's like n = SquareRoot(Pow(x,2)+Pow(y,2)), but I would have use for 3rd number, z.

 

[Ceday]

Hope you are using x*x instead of Pow =))

 

[Deleted member 219079]

Yes I do, that was only an example

 

[Ceday]

pythagoras should be sqrt(a^2 + b^2 + c^2) or no?

 

[Deleted member 219079]

I hope it works like that, thanks

By default, pythagors would be like:
Catetus^2 + Catetus^2 = Hypotenuse

Edit:
Um, is it certain to work with that? Just wondering..

 

[PurgeandFire]

I'm guessing you're using this for distance (x1, y1, z1) to (x2, y2, z2)? If so, then yes, sqrt((x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2) would work. See:
http://wc3jass.com/5050/snippet-geometrylibbase/

You can use that function (GetDistanceZ) as a reference.

 

[Deleted member 219079]

Yes, I'm using those. I'll test SquareRoot( dx * dx + dy * dy + dz * dz) in my system

Solved, thanks