Need A Mathematic Graph for this

[jonhysone]

Well I need a graph for this mathematic function .
It's related to a jump system .

Function

Constants :

• Set g_Acceleration = 981.00
• Set t_TimeStep = 0.03
• Set h_JumpHight = 300.00

Well If a player presses up

• Set x = 1000.00

So When x = 1000 this function runs

• Set x = (x - (g_Acceleration x t_TimeStep))

The Unit will be moved by this :

• Set _tempPointDXD_2D = (Position of Jumper)
• Set JumpTempPoint = (_tempPointDXD_2D offset by ((0, (X x t_TimeStep)))

This moves the unit :

• Unit - Move Jumper instantly to JumpTempPoint

When the jumper reaches the ground :

• Set X = 29.43

Can you give me a possible graph for this Oo ?

 

[Rheiko]

nooooo, don't math! i can't math! math is my weaknesess.. i'm gonna dieee!
sorry 'bout that, a little habit of mine..
the answer is "NO"

 

[jonhysone]

nooooo, don't math! i can't math! math is my weaknesess.. i'm gonna dieee!
sorry 'bout that, a little habit of mine..
the answer is "NO"

Call hospital guys lol

 

[Rheiko]

Click to

ambulance here!
anyway, you can use calculator perhaps?

 

[Malhorne]

Explain clearly the function like f(x) = ... and i will uplload them.

 

[jonhysone]

^That's the problem , I can't seem to get the f(x) , otherwise I would have gotten it with MathXpert oO .

 

[Malhorne]

Ok i'll try to see it later ...
EDIT : f(?) = ? Give me what you want in function of what

 

[jonhysone]

lol? It's seems that it's a x^2 function since it is related to a parabola jump .

 

[Malhorne]

Parabola jump : -gt²/2 + Vo*sin(angle)t + height initial
For a normal a parabola....
I didn't say for yours

 

[jonhysone]

^o___________O explain lol
And alos z should be constant , it's like platform escape jumps, I mean 2D very 2D

 

[Malhorne]

It's physic ^^
Second Newton's law ^^

 

[jonhysone]

It's physic ^^
Second Newton's law ^^

I'm going to study this in the next year . So I can't wait oo

 

[Malhorne]

Explain what you want in function of what :S

 

[jonhysone]

Well my goal is to know which X makes Unit- Move Unit's Y become 0 . That's all lol

 

[Malhorne]

I don't really understand write this in mathematic language i will understand ^^

 

[jonhysone]

I wish I am correct:
f(x) = ((X - (981 x 0.03))) x 0.03 . x Starts by 1000 . dunno by what it ends

 

[Malhorne]

And you want to find what XD ?

 

[rulerofiron99]

Dude what.

You shouldn't use mathematics if you don't understand it, you'll only end up confusing yourself and those trying to help you.

From what I understand, you're trying to make a simple 2D jump system, and you're struggling with the exit condition.

With those values you are using, the jump will be done in 0.06 seconds.

Try these values:
InitialVelocity = 10 . . . . . (at 33 iterations per second, this means the starting speed is 330 "warcraft speed")
Gravity = 1 . . . . . . (so it will take 10 iterations to reach the top of the jump, and another 10 iterations to reach the ground, so the jump will take 0.6 seconds total)

 

[Dr Super Good]

Use mathimatica or matlab, both do everything you ever need with mathematics.

 

[Malhorne]

Maxima is good too but for high level mathematic x)

 

[Imp Midna]

Hard to believe that, after 20 posts, nobody posted a simple graph. I, for myself, suck at maths, but i am at least good enough to type functions into a calculator (or for that matter, wolfram alpha), so here is my try:

x: f(x) = f(x-1) - (k*kt)
y: y(x) = y(x-1) + f(x)*kt
-----------------
f(x) = 1000 - kt*k*x
y(x) = c1 - 1/2 * kt*x*(kt*k*(x+1) - 2000)
with c1 being the initial y value of that unit (probably 0 i guess), and the x from y(x) increasing by 1 every time you calculate (probably every 0.03 seconds), k being 981 (acceleration) and kt being 0.03 (TimeStep).

Graph

With its maxima being located at x ≈ 33.48 and y(x) ≈ 495, reached after 34*0.03=1.02 seconds,
and the roots being at x=0 (douh) and x≈66.958, reached after 67*0.03=2.01 seconds.
A 2 second jump seems a little bit long imho. Anybody seeing any mistakes i made?

 

[Malhorne]

Yes that's a parabola but since it's a jump it was kinda obvious ^^