Computer Logic - (1 && !(0 || 1)) How does this equate 0?

[Nackel]

Can anyone break it down, i'm sure theres some little detail i'm missing..
(1 && !(0 || 1)) = 0 = False?

But how?

I can't make sense of how the first 1 somehow become 0.
Thanks.

 

[tagg1080]

Can anyone break it down, i'm sure theres some little detail i'm missing..
(1 && !(0 || 1)) = 0 = False?

But how?

I can't make sense of how the first 1 somehow become 0.
Thanks.

wait, what?

there are no variables?

1 and not(0 or 1)

that makes NO sense, what are you trying to do?

 

[Nackel]

I'm sorry this is C++ and I figured it was close enough to Jass that someone would understand, I'm trying to learn C++ but the question they gave me was: Evaluate: !(1 && !(0 || 1))
A. True
B. False

And the answer ended up being True.
But for it to be true, !(1 && !(0 || 1)) would have to end up being !0.
0 = False, 1 = True.
Very confusing.

 

[tagg1080]

!(1 && !(0 || 1))

Not(1 and Not(0 or 1))
--0 or 1 is true

Not(1 and Not(true)
--Not(true) is false

Not(1 and false)
--(1 and false) is false

Not(false)
is true...

 

[Nackel]

Ok so 1 && False is False.
And False || True is True?

Thanks, that's all I needed to know.

 

[Dr Super Good]

Okay.... What does this have to do with JASS????

All I see is a set of comparitive opperators from java or other C like languages. I am not aware of these being availble to use in JASS code.

 

[tagg1080]

Ok so 1 && False is False.
And False || True is True?

Thanks, that's all I needed to know.

That is pretty basic logic, yes.

True OR False = True
--because it is asking if either one is true

True AND False = False
--because it is asking if BOTH are true


Dr. Super: This kind of logic applies to programming logic in general, what is the problem with someone asking?

 

[Dr Super Good]

"Triggers & Scripts Discussions regarding GUI triggers & JASS/AI scripts may be found here. Please review the » JASS Tutorials » Trigger Tutorials"

Nowhere does it say this is the place for general programming help. Moved to a different section.

 

[Cokemonkey11]

Can anyone break it down, i'm sure theres some little detail i'm missing..
(1 && !(0 || 1)) = 0 = False?

But how?

I can't make sense of how the first 1 somehow become 0.
Thanks.

Remember to start with the most nested quotes.

(1 && !(0 || 1))

False OR True is TRUE.

Right outside the parenthesis is NOT (think like the distributive property). NOT TRUE is False.

So now we have 1 && FALSE

TRUE && FALSE requires that both statements are true to return true; since they aren't, the answer is FALSE.

Hope that helped.