[JASS] 2 More math questions

[Dynasti]

Ok i need 2 more values.

You are given 3 variables

1. Real value ' D ' ( Distance )
2. Real value ' T ' ( Time it takes )
3. real value ' I ' ( Interval )

I need 2 values.

1. ' SS ' ( Start Speed )
2. ' SD ' ( Speed Decrease )

The ' SS ' is the starting speed and the ' SD ' is a value that is drawn from the starting speed every interval. Like some sort of knockback. It starts at ' SS ' and ends at 0. I want a decending speed so need 2 values.( The starting speed and the decreasing speed )

You are given 3 variables

1. Real value ' D ' ( Distance )
2. Real value ' T ' ( Time it takes )
3. real value ' I ' ( Interval )

I need 2 values.

1. ' SI ' ( Speed )
2. ' ES ' ( End Speed )

The first ' ES ' is the ending speed and the ' SI ' value is a value that is used to increase the speed every interval. Like some sort of reversed knockback. It starts at 0 and ends at the ' ES '. I want a increasing speed so need 2 values.( End speed and increasing speed )

 

[Justify]

Awww, is the time that important? xD Because, SS = D/T, the problem ist that when you decrease SS every I by SD, either the time increases or the distance decreased... a formula that gives you SS and SD for T and D is just too complitcated :/

 

[Dynasti]

Awww, is the time that important? xD Because, SS = D/T, the problem ist that when you decrease SS every I by SD, either the time increases or the distance decreased... a formula that gives you SS and SD for T and D is just too complitcated :/

no it is not too complicated

 

[GhostWolf]

1. There are infinite solutions, you must give either of those as a parameter.

To get the initial velocity:

v0 = (-0.5*a*t+ (x - x0)/t)*FPS

v0 being the initial velocity.
a being the acceleration.
t being the time.
x being the final position.
x0 being the initial position.
FPS being 1/interval.

Which is the physics quotation for position<->time given a constant acceleration.

v = v0 + at would give you the velocity at any time, but given that the time you want is 0, at = 0, and thus v = v0.

In case you care, the original quotation looks like this:
x = x0 + v0t + 1/2(at*at)

2. Again, there are infinite possibilities, and it makes no sense.
You must to give either of those as a parameter.

Given the acceleration, you would do it like this:
v = v0 + at = 0 + at = at

 

[Dynasti]

1. There are infinite solutions, you must give either of those as a parameter.

To get the initial velocity:

v0 = (-0.5*a*t+ (x - x0)/t)*FPS

v0 being the initial velocity.
a being the acceleration.
t being the time.
x being the final position.
x0 being the initial position.
FPS being 1/interval.

Which is the physics quotation for position<->time given a constant acceleration.

v = v0 + at would give you the velocity at any time, but given that the time you want is 0, at = 0, and thus v = v0.

In case you care, the original quotation looks like this:
x = x0 + v0t + 1/2(at*at)

2. Again, there are infinite possibilities, and it makes no sense.
You must to give either of those as a parameter.

Given the acceleration, you would do it like this:
v = v0 + at = 0 + at = at

so for the second question, is SI(speed increasement) = v = v0 + at = 0 + at = at? What is the ES(Ending Speed, the loop will exit when a value that counts the speed is greater than the end speed)

 

[GhostWolf]

SI = a = acceleration.
SE = SI*Time when Time is the biggest value that can be given, so if you want it to run 5 seconds, Time would be 5.

What do you need all this formulas for anyway?

 

[Dynasti]

SI = a = acceleration.
SE = SI*Time when Time is the biggest value that can be given, so if you want it to run 5 seconds, Time would be 5.

What do you need all this formulas for anyway?

some random system.

The variable ' v ' is not given. You are only given distance, time, and an interval( usually 0.01 - 0.035 )

 

[GhostWolf]

You have to give it a velocity. If it has non it can have infinite answers and it won't make sense anyway.

That velocity can be at any given time, but you have to give it a velocity of at least one "key frame" of your movement.

 

[Dynasti]

i got formula right here.

local integer q = R2I(T / I)
SE = 2 * D / (q + 1)
SI = SE / q

 

[Rmx]

I know the Perfect solution just look at my spellpack The Triger Shooting Star there is some documentation And the Formula u will see i used this for my knockback spell http://www.hiveworkshop.com/forums/spells.php?id=mql033&prev=u=Rmx