Hey, I saw your Math question in your signature and I managed to solve it. Here is the solution:
2x sqrt (1 - 2x2) + ( - [2x / sqrt (1 - 2x2)] ) x2
Multiply x2 by the fraction in the brackets to get:
2x sqrt (1 - 2x2) - (2x3 / sqrt [1 - 2x2] )
I removed the plus sign because the fraction is negative. The brackets were removed because I expanded. Now here comes the hard part... uniting both parts as a single fraction. This can be done by multiplying the denominators by each other (1 and sqrt [1 - 2x2]) and by cross multiplication.
2x (sqrt [1 - 2x2] × sqrt [1 - 2x2]) - 2x3 / sqrt (1 - 2x2)
Multiplying the square roots eliminates them and leaves only one of the expressions behind so:
2x (1 - 2x2) - 2x3 / sqrt (1 - 2x2)
Expand the brackets and simplify to get:
2x - 6x3 / sqrt (1 - 2x2)
2x sqrt (1 - 2x2) + ( - [2x / sqrt (1 - 2x2)] ) x2
Multiply x2 by the fraction in the brackets to get:
2x sqrt (1 - 2x2) - (2x3 / sqrt [1 - 2x2] )
I removed the plus sign because the fraction is negative. The brackets were removed because I expanded. Now here comes the hard part... uniting both parts as a single fraction. This can be done by multiplying the denominators by each other (1 and sqrt [1 - 2x2]) and by cross multiplication.
2x (sqrt [1 - 2x2] × sqrt [1 - 2x2]) - 2x3 / sqrt (1 - 2x2)
Multiplying the square roots eliminates them and leaves only one of the expressions behind so:
2x (1 - 2x2) - 2x3 / sqrt (1 - 2x2)
Expand the brackets and simplify to get:
2x - 6x3 / sqrt (1 - 2x2)